What happens if you try to compile and run this program?

#include

int main (int argc, char *argv[]) {

int i = 2;

int d= i << 2;

d /= 2;

printf ("%d", d) ;

return 0;

}

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What happens when you compile and run the following program?

#include

int fun(void) {

static int i = 1;

i++;

return i;

}

int main (void) {

int k, l;

k = fun ();

l = fun () ;

printf("%d",l + k);

return 0;

}

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What is the meaning of the following declaration?

float ** p;

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What happens if you try to compile and run this program?

#include

int main (int argc, char *argv[]) {

int i = 1, j = 0;

int 1 = !i + !! j;

printf("%d", 1);

return 0;

}

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What happens if you try to compile and run this program?

#include

int *fun(int *t) {

return t + 4;

}

int main (void) {

int arr[] = { 4, 3, 2, 1, 0 };

int *ptr;

ptr = fun (arr - 3);

printf("%d \n", ptr[2]);

return 0;

}

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What happens if you try to compile and run this program?

#include

int main (int argc, char *argv[]) {

int main, Main, mAIN = 1;

Main = main = mAIN += 1;

printf ("%d", MaIn) ;

return 0;

}

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What happens if you try to compile and run this program?

#include

int main (int argc, char *argv[]) {

int i =2, j = 1;

if(i / j)

j += j;

else

i += i;

printf("%d",i + j);

return 0;

}

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What happens if you try to compile and run this program?

#include

fun (void) {

static int n = 3;

return --n;

}

int main (int argc, char ** argv) {

printf("%d \n", fun() + fun());

return 0;

}

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What happens if you try to compile and run this program?

#include

int main (int argc, char *argv[]) {

int i = 1;

for( ;; i/=2)

if(i)

break ;

printf("%d",i);

return 0;

}

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The program executes an infinite loop

What happens if you try to compile and run this program?

#include

int main (int argc, char *argv[]) {

char *t = "abcdefgh";

char *p = t + 2;

int i;

p++;

p++;

printf("%d ", p[2] - p[-1]);

return 0;

}

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What happens when you compile and run the following program?

#include

int fun (void) {

static int i = 1;

i += 2;

return i;

}

int main (void) {

int k, 1;

k = fun ();

1 = fun () ;

printf ("%d", 1 - k);

return 0;

}

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What happens if you try to compile and run this program?

#include

int main (int argc, char *argv[]) {

float f = 1e1 + 2e0 + 3e-1;

printf("%f ",f);

return 0;

}

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